JQL: principles for dealing with names with spaces

  • 1 September 2020
  • 1 reply

Badge +2

Hi there!

I have the following line of code, and need to change the name of the variable from First_Seen to First Seen.

Wondering if anyone can help advise as to how I should change it to be able to recognize the property with a space instead of underscore? 

.filter(function(some_variable){return ! Seen})


Thank you!

1 reply

Userlevel 6
Badge +3

@robyn-dunne —

I think you will want to put your property name in “quotes” — does that help?


I assume you’ve already seen this JQL documentation, but just in case someone is running into a similar issue I want to link it here.